The values of `K_(p_(1))` and `K_(p_(2))` for the reactions
`X hArr Y+Z` ….(i)
and `A hArr 2B` …(ii)
are in ratio of 9 : 1. If degree of dissociation of X and A be equal, then total presure at equilibrium (i) and (ii) are in the ratio.

Options

A. `36:1`
B. `1:1`
C. `3:1`
D. `1:9`

Answer

A

Explanation

`{:(XhArrY+Z" ...(1)"),(AhArr2B" ...(2)"),(XhArr Y+Z" ):}`
`{:("Initially",1,0,0),("At eq.",1-alpha,alpha, alpha):}`
Total no. of moles at equilibrium
`=1-alpha+2alpha=1+alpha`
`{:(,A,hArr,2B),("Initially, when t = 0",1,,0),("At eq. ",1-alpha,,2alpha):}`
Total no. of moles at equilirium
`=1-alpha+2alpha=1+alpha`
`K_(p_(2))=((P_(B))^(2))/(P_(A))=([(2alpha//1+alpha)xxP_(2)]^(2))/([1-alpha//1+alpha]xxP_(2))`
`(K_(P_(1)))/(K_(P_(2))=(P_(1))/(4P_(2))`
`(P_(1))/(P_(2))=(36)/(1)=36:1`