`0.002m` aqueous solution of an ionic compound `Co(NH_(3))_(5)(NO_(2))CI` freezes at `-0.00732^(@)C`.Number of moles of ions which 1 mole of ionic compound produces in water will be `(K_(f) = 1.86^(@)C//m)`

Options

A. 1
B. 2
C. 3
D. 4

Answer

B

Explanation

`DeltaT_(f)=ik_(f).m`
`i=(DeltaT_(f))/(k_(f).m)`
`=(0.00732)/(1.86xx0.002)=(0.00732)/(0.00372)`
`i=2`
Compound will be `[Co(NH_(3))_(5)]NO_(5)NO_(2)]Cl`
Total possible ions =2