The reaction,
`2A(g) + B(g)hArr3C(g) + D(g)`
is begun with the concentration of A and B both at an intial value of `1.00` M. When equilibrium is reached, the concentration of D is measured and found to be `0.25` M. The value for the equilibrium constant for this reaction is given by the expression:

Options

A. `[(0.75)^(3)(0.25)] div [(0.50)^(2)(0.75)]`
B. `[(0.75)^(3) (0.25)] div [(0.50)^(2)(0.25)]`
C. `[(0.75)^(3)(0.25)] div [(0.75)^(2)(0.25)]`
D. `[(0.75)^(3)(0.25)]div [(1.00)^(2)(1.00)]`

Answer

A