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A 0.1 molal aqueous solution of a weak a...

A `0.1` molal aqueous solution of a weak acid is `30%` ionized. If `K_(f)` for water is `1.86^(@)C//m`, the freezing point of the solution will be.

A

`-0.24^(@)C`

B

`-0.18^(@)C`

C

`-0.54^(@)C`

D

`-0.36^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`i=1-alpha+nalpha`
i=1-0.3+2(0.3)
i=1.3
`DeltaT_f=iK_fm`
`=1.3xx1.86xx0.1`
`DeltaT_f=+0.24^@C`
Freezing point of solution = `-0.24^@C`
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