A solution contains `Fe^(2+), Fe^(3+)` and `T^(-)` ions. This solution was treated with iodine at `35^(@)C. E^(@)` for `Fe^(3+), Fe^(2+)` is `0.77 V` and `E^(@)` for `I_(2)//2I^(-)` = 0.536 V. The favourable redox reaction is:

Options

A. `Fe^(2+)` will be oxidized to `Fe^(3+)`
B. `I_(2)` will be the reduced to `I^(-)`
C. There will be no redox reaction
D. `I^(-)` will be oxidized to `I_(2)`

Answer

D

Explanation

`2Fe^+3+2I^(-) to I_2+2Fe^(+2)`