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200 mL of an aqueous solution of a prote...

200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be `2.57 xx 10^(-3)` bar. The molar mass of protein will be `(R = 0.083 L bar mol^(-1)K^(-1))`

A

`61038 g mol^(–1)`

B

`51022 g mol^(–1)`

C

`122044 g mol^(–1)`

D

`31011 g mol^(–1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`piv=w/mRT`
`2.5xx10^-3xx200/1000=1.26/mxx0.083xx300`
m=61038 gm `mol^-1`
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