Given the reaction between 2 gases represented by `A_(2)` and `B_(2)` to given the compound AB(g). `A_(2)(g) + B_(2)(g)hArr 2AB(g)`
At equilibrium, the concentrtation
of `A_(2) = 3.0xx10^(-3) M`
of `B_(2) = 4.2xx10^(-3) M`
of `AB = 2.8xx10^(-3) M`
If the reaction takes place in a sealed vessel at `527^(@)C` . then the value of `K_(c)` will be

Options

A. 1.9
B. 0.62
C. 4.5
D. `2.0`

Answer

B

Explanation

`underset((g))(A_(2))+underset((B))(B_(2))hArr underset((g))(2AB)`
`K_(c)=([AB]^(2))/([A_(2)][B_(2)])=(2.8xx2.8xx10^(-6))/(3xx10^(-3)xx4.2xx10^(-3))=0.62`