Correct set of four quantum numbers for the valence (outermost) electron of rubidium `(Z = 37)` is

Options

A. `5,0,0,+(1)/(2)`
B. `5,1,0,+(1)/(2)`
C. `5,1,1,+(1)/(2)`
D. `6,0,0,+(1)/(2)`

Answer

A

Explanation

`Rb(37)=[kr]5s^(1)`
`n=5,1=0. m=0,s=+1//2`