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The value of Planck's constant is 6.63 x...

The value of Planck's constant is `6.63 xx 10^(-34)Js`. The speed of light is `3xx10^(17)nm s^(-1)`. Which value is the closed to the wavelength in nanometers of a quantum of light with frequency `6 xx 10^(10)s^(-1)`?

A

10

B

25

C

50

D

75

Text Solution

Verified by Experts

The correct Answer is:
C
`h=6.63xx10^(-34)Js.`
`C=3xx10^(7) nm//sec.`
`lambda=6xx10^(15)sec^(-1)`
`lambda=(C)/(v)=(3xx10^(17))/(6xx10^(15))=50 nm`
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