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Based on equation E = -2.178 xx 10^-18 J...

Based on equation `E = -2.178 xx 10^-18 J((Z^2)/(n^2))`, certain conclusions are written. Which of them is not correct ?

A

The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus.

B

Larger the value of n, the larger is the orbit radius.

C

Equation can be used to calculate the change in energy when the electron changes orbit.

D

For n = 1, the electron has a more negative energy that it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit.

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The correct Answer is:
D

As we move nearer to the nucleus `e^(-)` are more strongly bonded.
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Energy of an electron is given by E = - 2.178 xx 10^-18 J ((Z^2)/(n^2)) . Wavelength of light required to excite an electron in an hydrogen atom from level n = 1 to n = 2 will be (h = 6.62 xx 10^-34 Js and c = 3.0 xx 10^8 ms^-1 ).

Energy in the nth Bohr's is given by E = (-2.179 xx 10^(-18))/(n^(2)) J s Calculate the frequency and wave number of the radiation emitted when an electron jumps from the third orbit to the second orbit (h = 6.62 xx 10^(34) J s)

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