`6.02xx10^(20)` molecules of urea are present in 100 ml of its solution. The concentration of solution is :

Options

A. 0.02 M
B. 0.01 M
C. 0.001 M
D. 0.1 M

Answer

B

Explanation

`M=("mole")/(V_((ml)))xx1000=(0.001)/(100)xx1000=0.01 M`