A `20` litre container at `400 K` contains `CO_(2) (g)` at pressure `0.4 atm` and an excess of `SrO` (neglect the volume of solid `SrO`). The volume of the container, when pressure of `CO_(2)` attains its maximum value, will be:
(Given that: `SrCO_(3)(s) hArr SrO(s) +CO_(2)(g)K_(p) =1.6 atm`)

Options

A. 5 litre
B. 10 litre
C. 4 litre
D. 2 litre

Answer

A

Explanation

Max. pressure of `CO_(2)` = Pressure of `CO_(2)` at equilibrium
For reaction ,
`SrCO_(3) (s) iff SrO (s)+CO_(2)`
`K_(p)=P_(CO_(2))=1.6"atm"`= maximum pressure of `CO_(2)`
Volume of container at this stage ,
`V=(nRT)/(P)` ....... (i)
Since container is sealed and reaction was not earlier at equilibrium
`:.` n=constant
`n=(PV)/(RT)=(0.4xx20)/(RT)` .....(ii)
Put equation (ii) in equation (i)
`V=[(0.4xx20)/(RT)](RT)/(1.6)=5L`