Pick out the correct statement with respect to `[Mn(CN)_(6)]^(3-)`:

Options

A. It is `sp^(3)d^(2)` hybridised and octahedral
B. It is `sp^(3)d^(2)` hybridised and tetrahedral
C. It is `d^(2)sp^(3)` hybridised and octahedral
D. It is `dsp^(2)` hybridised and square planar

Answer

C

Explanation

`[Mn(CN)_(6)]^(3-)`
Mn(III)`=[Ar]3d^(4)`
`CN^(-)` being strong field ligand forces pairing of electrons
This gives `t_(2g)^(4)e_(g)^(0)`
`:. Mn(III)=[Ar]`

`:'` Coordination number of Mn=6
`:.` Structure= octahedral
`[Mn(CN)_(6)]^(3-)=`