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An element with density 11.2 g cm^(-3) f...

An element with density `11.2 g cm^(-3)` forms a f. c. c. lattice with edge length of `4xx10^(-8)` cm. Calculate the atomic mass of the element. (Given : `N_(A)= 6.022xx10^(23) mol^(-1)`

Text Solution

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The correct Answer is:
`24.12 xx 10^(23) ` atoms
`p (Z xx M)/( a^(3)xx N_(A)) ` For element with f.c.c. lattice, Z = 4
` M = ( p xx a^(3) xx N_(A))/ Z = (( 11.2 " g cm"^(-3)) ( 4xx 10^(-8) "cm")^(3) xx ( 6.022 xx 10^(23) "mol"^(-1)))/4 = 107.9 " g mol"^(-1)`
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