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The unit cube length for LiCl (NaCl stru...

The unit cube length for `LiCl` (`NaCl` structure) is `5.14 Å`. Assuming anion-anion contact, calculate the ionic radius for chloride ion.

Text Solution

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The correct Answer is:
(i) 329 pm (ii) 139 pm
Interionic distance of LiCI = `(5.14)/2 = 2.57Å`
` BC = sqrt( AB^(2) + AC^(2)) = sqrt((2.57)^(2) + (2.57)^(2)) = 3.63`
Radius of ` Cl^(-)` ion ` 1/2 xx 3.63 Å = 1.81 Å`
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