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Structure of a mixed oxide is cubic clos...

Structure of a mixed oxide is cubic closed - packed (ccp) .The cubic unit cell of mixed oxide is composed of oxide ions .One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovelent metal B .The formula of the oxide is

A

`A_(2)B_(3)O_(4)`

B

`AB_(2)O_(2)`

C

`ABO_(2)`

D

`A_(2)BO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Suppose number of ` O^(2-)` ions in close packing = n
No. of octahedral voids = n
No. of tetradral voids = 2n
Divalent metal ions A present = `(2n)/4 = n/2 `
Monovalent metal ions B present =n
Ratio `A :B : O^(2-) = n/2 : n :n = 1/2 :1:1 `
Hence, formula = ` AB_(2)O_(2)`
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