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A solid compound XY has NaCl structure. ...

A solid compound `XY` has `NaCl` structure. If the radius of the cation is `100` pm, the radius of the anion `(Y^(-))` will be

A

275.1

B

322.5 pm

C

241. 5 pm

D

165. 7 pm

Text Solution

Verified by Experts

The correct Answer is:
B
NaCl and face-centred cubic arrangement of ` Cl^(-)` ions and `Na^(+)` ions are present in the octahedral voids. Hence, for such a solid , radius , of cation
=` 0. 414 xx " radius of the anion " ( or (r_(+))/(r_(-)) = 0.414)`
i.e, ` r_(+) = 0.414 xx r_(-)`
`or = r_(-) = ( r_(+))/(0.414) = 100/(0. 414) = 241. 5 "pm" `
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