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The ionic radii of A^(+) and B^(-) ions ...

The ionic radii of `A^(+) and B^(-)` ions are `0.98 xx 10^(-10) and 1.81 xx 10^(-10) m` .The coordinatyion number of each ion in `AB` is

A

2

B

6

C

4

D

8

Text Solution

Verified by Experts

The correct Answer is:
A
Radius ratio , ` r_(+)/r_(-) = ( 0.98 xx 10^(-10))/( 1.81 xx 10^(-10)) = 0.541`
It liess in the range 0.414 - 0.732. Hence, coordination number of each ion will be 6, as in the case of NaCl.
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