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Ice crystallises in a hexagonal lattice ...

Ice crystallises in a hexagonal lattice having a volume of the unit cell as ` 132 xx 10^(-24) cm^(3)` . If density of ice at the given temperature is 0.92 `g cm^(-3)`, the number of ` H_(2)O` molecules per unit cell is

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
b
` p = ( Z xx M)/(a^(3) xxN_(0)) ` , the aim is to find Z.
` 0.92 = ( Z xx 18)/((132 xx 10^(-24)) ( 6.02 xx 10^(23))) `
` ( Z xx 18) /(132 xx 6.02 xx 10^(-1))`
`or Z = ( 0.92 xx 132 xx 6.02 xx 10^(-1))/18 = 4.06`
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