Calculate (a) Wavenumber and (b) frequency of yellow radiation having wavelength `5800 A^(@)`.

Explanation

Calculate of wave number: Wave number `bar(v) = (1)/(lambda)`
But `lamda = 5800Å = 5800 xx 10^(-10)m " (Given)" :. bar(v) = (1)/(5800 xx 10^(-10)m) = 1.72 xx 10^(6) m^(-1)`
(b) Calculate of Frequency: Frequency `v = (c)/(lamda)`
Substituting `c = 3 xx 10^(8) m//sec and lamda = 5800 xx 10^(-10)m`, we get
`v = (3 xx 10^(8) ms^(-1))/(5800 xx 10^(-10)m) = 5.172 xx 10^(14) s^(-1)` or cycles/sec or Hz