Calculate the kinetic energy of the electron ejected when yellow light of frequency `5.2 xx 10^(14) sec^(-1)` falls on the surface of potassium metal. Threshold frequency of potassium is `5 xx 10^(14) sec^(-1)`

Explanation

To calculate the kinetic energy of the electron ejected when yellow light falls on the surface of potassium metal, we can follow these steps:

### Step 1: Understand the Problem
We need to find the kinetic energy (KE) of an electron ejected from potassium when exposed to yellow light of a certain frequency. We are given:
- Frequency of yellow light, \( f = 5.2 \times 10^{14} \, \text{s}^{-1} \)
- Threshold frequency of potassium, \( f_0 = 5.0 \times 10^{14} \, \text{s}^{-1} \)

### Step 2: Use the Photoelectric Equation
...