Calculate the wavelength associated with an electron (mass `9.1 xx 10^(-31)kg`) moving with a velocity of `10^(3) m sec^(-1) (h = 6.6 xx 10^(-34) kg m^(2) sec^(-1))`

Explanation

Here, we are given: `m = 9.1 xx 10^(-31) kg, v = 10^(3) m sec^(-1), h = 6.6 xx 10^(-34) kg m^(2) s^(-1)`
`lamda = (h)/(mv) = (6.6 xx 10^(-34) kg m^(2) s^(-1))/((9.1 xx 10^(-31) kg) xx (10^(3) ms^(-1))) = 7.25 xx 10^(-7) m`