A microscope using suitable photons is employed to locate an electron in an atom within a distance of 0.1 Ã…. What is the uncertainty involved in the measurement of its velocity ?

Explanation

Here, we are given: `Delta x = 0.1 Å = 0.1 xx 10^(-10) m = 10^(-11) m`
`h = 6.626 xx 10^(-34) kg m^(2) s^(-1), m = 9.11 xx 10^(-31) kg`
Applying uncertainty principle, `Delta x. (m Delta v) = (h)/(4pi)`
i.e., `Delta v = (h)/(4pi xx m xx Delta x) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/(4 xx 3.14 xx 9.11 xx 10^(-31) kg xx 10^(-11) m) = 5.79 xx 10^(6) ms^(-1)`