Calculate the range of frequencies of visible light from `3800 - 7600 Å`

Answer

`3.95 xx 10^(14) " to " 7.89 xx 10^(14) s^(-1)`

Explanation

`lambda = 3800 Å = 3800 xx 10^(-10) m = 3.8 xx 10^(-7) m, " " v = (c)/(lamda) = (3 xx 10^(8) ms^(-1))/(3.8 xx 10^(-7) m) = 7.89 xx 10^(14) s^(-1)`
`lamda = 7600 Å = 7600 xx 10^(-10) m = 7.6 xx 10^(-7) m, " " v = (c)/(lamda) = (3 xx 10^(8) ms^(-1))/(7.6 xx 10^(-7) m) = 3.95 xx 10^(14) s^(-1)`