Applyig bohr's model when H-atom comes from n=4 to n=2, calcualte its wavelength. In this process, write whether energy is released or aborbed? Also write the range of radiation `R_(H)=2.18xx10^(-18)J,h=6.63xx10^(-34)J-s`

Answer

`4866 Å`, Energy is released. It lies in the visible range.

Explanation

Apply Rydberg's formula, `E = (hc)/(lamda) = R_(H) Z^(2) ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
For H-atom, Z = 1
n = 4 or n = 2 means `n_(2) = 4, n_(1) = 2`
Calculate `lamda`