Calculate de Broglie wavelength of an electron travelling at `1 %` of the speed of light.

Answer

`2.4 xx 10^(-10)m = 2.4 Å`

Explanation

`v = 1% " of " 3 xx 10^(8) ms^(-1) = 3xx 10^(6) m s^(-1), m_(e) = 9.11 xx 10^(-31) kg`