The sodium flame test has a characteristic yellow colour due to the emission of a wavelength of `589 nm`. What is the mass equivalent of one photon of this wavelength?

Answer

`3.75 xx 10^(-36)kg`

Explanation

`lamda = (h)/(mv) or m = (h)/(lamda xx v) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/((589 xx 10^(-9)) (3 xx 10^(8) ms^(-1))) = 3.75 xx 10^(-36) kg`