Calculate the ratio between the wavelength of an electron and a proton, if the proton is moving at half the velocity of the electron (mass of the proton `=1.67xx10^(-27)kg`, mass of the electron`=9.11xx10^(-2)m`.

Answer

916.6

Explanation

`lamda_(e) = (h)/(m_(e) v_(e)), lamda_(p) = (h)/(m_(p) v_(p)), (lamda_(e))/(lamda_(p)) = (m_(p) v_(p))/(m_(e) v_(e)) = (1)/(2) xx (1.67 xx 10^(-27) kg)/(9.11 xx 10^(-31) kg) = 916.6`