Calculate the minimum uncertainty in velocity of a particle of mass `1.1 xx 10^(-27) kg` if uncertainty in its position is `3 xx 10^(-10)cm`. `(h= 6.62 xx 10^(-34)kg.m^(2) s^(-1))`

Answer

`1.59 xx 10^(4) ms^(-1)`

Explanation

`Delta x = 3 xx 10^(-10) cm 3 xx 10^(-12) m`