Give the value of the quantum numbers for the electron with the highest energy in sodium atom

Explanation

To determine the quantum numbers for the electron with the highest energy in a sodium atom, we will follow these steps:

### Step 1: Determine the Atomic Number of Sodium
Sodium (Na) has an atomic number of 11, which means it has 11 electrons.

### Step 2: Fill the Electron Shells
We will fill the electron shells according to the Aufbau principle:
- The first shell (n=1) can hold 2 electrons: **1s²**
- The second shell (n=2) can hold 8 electrons: **2s² 2p⁶**
- The third shell (n=3) can hold more electrons, but we will fill it according to the number of electrons we have.

Filling the electrons:
- 1s² (2 electrons)
- 2s² (2 electrons)
- 2p⁶ (6 electrons)
- This accounts for 10 electrons, leaving us with 1 electron to place in the next available orbital, which is 3s.

So, the electron configuration of sodium is: **1s² 2s² 2p⁶ 3s¹**

### Step 3: Identify the Highest Energy Electron
The highest energy electron in sodium is the one in the outermost shell, which is in the 3s orbital.

### Step 4: Determine the Quantum Numbers
Quantum numbers are defined as follows:
- Principal quantum number (n): Indicates the main energy level. For the highest energy electron in sodium, n = 3.
- Azimuthal quantum number (l): Indicates the subshell. For an s orbital, l = 0.
- Magnetic quantum number (m): Indicates the orientation of the orbital. For an s orbital, m = 0.

Thus, the quantum numbers for the highest energy electron in sodium are:
- n = 3
- l = 0
- m = 0

### Final Answer:
The quantum numbers for the electron with the highest energy in a sodium atom are:
- n = 3
- l = 0
- m = 0

---