The diameter of zinc atom is `2.6 A`. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of `1.6 cm` if the zinc atoms are arranged side by side lengthwise.

Explanation

(a) Radius `= (2.6 Å)/(2) = 1.3 Å = 1.3 xx 10^(-10) m = 130 xx 10^(-12) m = 130`pm
(b) Given length `= 1.6 cm = 1.6 xx 1-^(-2) m`
Diameter of one atom `= 2.6 Å = 2.6 xx 10^(-10)m`
`:.` No of atoms present along the length `=(1.6 xx 10^(-2))/(2.6 xx 10^(-10)) = 6.154 xx 10^(7)`