Dual behaviour of matter proposed by de Broglie led to the discovery of electron microscope often used for the highly magnified images of biological molecules and other type of material. If the velocity of the electron in this microcope is `1.6xx10^(6) m s^(-1)`. Calculate de Broglie wavelength associated with this electron.

Explanation

`lamda = (h)/(mv) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/((9.11 xx 10^(-31) kg) (1.6 xx 10^(6) ms^(-1))) m = 4.55 xx 10^(-10) m = 455` pm