Wavelengths of different radiations are given below:
(A) 300nm (B) `300 mu m` (C) 3nm (`30A^(@)`
Arrange these radiations in the increasing order of their energies.

Explanation

`lamda (A) = 300nm = 300 xx 10^(-9) m = 3 xx 10^(-7) m, lamda (B) = 300 mu m = 300 xx 10^(-6) m = 3 xx 10^(-4) m lamda (C) = 3nm 3 xx 10^(-9)m, lamda (D) = 30 Å = 30 xx 10^(-10) m = 3 xx 10^(-9) m`
`E = hv = h (c)/(lamda)`. Thus, `E prop (1)/(lamda)`. Hence, increasing order of energy is `B lt A lt C = D`