In H-atoms, the energy of electron in the nth orbit is given as `E_(n) = - (13.6)/(n^(2)) eV`
Show that `E_((n +1)) - E_(n) = (13.6 xx 2)/(n^(3)) eV` for large value of n.

Explanation

To solve the problem, we need to show that the difference in energy between the (n+1)th orbit and the nth orbit in a hydrogen atom can be expressed as:

\[ E_{(n + 1)} - E_n = \frac{13.6 \times 2}{n^3} \, \text{eV} \]

### Step-by-Step Solution:

1. **Write the Energy Formula**:
The energy of an electron in the nth orbit of a hydrogen atom is given by:
...