A base ball of mass `200 g` is moving with velocity of `3 xx 10^(3) cm s^(-1)`. If we can locate the base ball with an error equal to the magnitude of the wavelength of the light used `(5000 Å)`. How will the uncertainty in momentum be used with the total momentum of the base ball?

Answer

`Delta p//p = 1.75 xx 10^(-31)`

Explanation

`m = 200//1000 = 0.2 kg, v = 30 xx 10^(2) m s^(-1), Delta x = 5000 Å = 5000 xx 10^(-10) m = 5 xx 10^(-7) m`
`Delta x. Delta p = h//4p pi`. Calculate `Deltap`. Also `p - mv`. Calculate `Delta p//p`