A metallic ion `M^(2+)` has an electronic configuration of 2, 8, 14 and the ionic weight is 56 amu. The number of neutrons in its nucleus is

Options

A. 30
B. 32
C. 34
D. 42

Answer

A

Explanation

E.C. of `M^(2+) = 2, 8, 14` i.e., it has 24 electrons. Hence, metal atom M would have electrons = 26
Hence, protons = 26, Neutrons `= A - Z = 56 - 26 = 30`