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The value of planok,s constant is 6.63x...

The value of planok,s constant is `6.63xx10^(-34)Js` the speed of light is` 3xx10^(17) nm s^(-1)` which value is closest to the wavelength in nanometer of a quantum of light with frequency of `6xx10^(15) S^(-1)`?

A

10

B

25

C

50

D

75

Text Solution

Verified by Experts

The correct Answer is:
C

`v = (c)/(lamda) or lamda = (c)/(v) = (3 xx 10^(17) nm s^(-1))/(6 xx 10^(15) x^(-1)) = 50 nm`
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