Which of the following is the energy of a possible excited state of hydrogen?

Options

A. `-3.4 eV`
B. `+ 6.8 eV`
C. `+ 13.6 eV`
D. `-6.8 eV`

Answer

A

Explanation

Energy of electron in the nth orbit of H-atom is
`E_(n) = - (13.6)/(n^(2)) eV, E_(2) = - (13.6)/(2^(2)) = - (13.6)/(4) = - 3.4 eV` (i.e., energy of first excited state)