how fast is an electron moving if it has a wavelength equal to the distance traveled in one second ?

Options

A. `sqrt((m)/(h))`
B. `sqrt((h)/(m))`
C. `sqrt((h)/(p))`
D. `sqrt((h)/(2(KE)))`

Answer

B

Explanation

Distance travelled in 1 sec = velocity (v)
Given `lamda = v`. Hence, `lamda = (h)/(mv)` becomes `v = (h)/(mv)`
or `v^(2) = (h)/(m) or v = sqrt((h)/(m))`