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A 5L cylinder contained 10 moles of oxyg...

A `5L` cylinder contained `10` moles of oxygen gas at `27^(@)C`. Due to sudden leakage through the hole, all the gas escaped into the atmosphere and the cylinder got empty. If the atmospheric pressure is `1.0atm`, calculate the work done by the gas.

Text Solution

Verified by Experts

`V_("initial") = 5L, T = 27^(@)C = 27 + 273 K = 300 K`
`V _("final") = (nRT)/(P) = (10 xx 0.0821 xx 300)/( 1.0) = 246.3L`
`Delta V = V_("final") - V_("initial") = 246.3 -5= 241.3 L`
`W _(exp) = - PDeltaV = - 1 xx 241.3 L atm= - 241.3 xx 101 . 3 J = - 24443.7 J`
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Knowledge Check

  • A cylinder contains 12 litres of oxygen at 20^(@)C and 15 atm pressure. The temperature of the gas is raised to 35^(@)C and its volume increased to 17 litres. What is the final pressure of gas (in atm)?

    A
    9
    B
    11
    C
    15
    D
    17
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    A
    `12.3 J`
    B
    `1246 J`
    C
    `-12.3 J`
    D
    `-1246 J`
  • A gas expands in volume from 2L to 5L against a pressure of 1 atm at constant temperature. The work done by the gas will be

    A
    3 J
    B
    `-303.9` J
    C
    `-303.9L*` atm
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    `303.9 L*`atm