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Two moles of an ideal gas initially at 2...

Two moles of an ideal gas initially at `27^(@)C` and one atmospheric pressure are compressed isothermally and reversibly till the final pressure of the gas is 10 atm calculate q, w and `Deltaw` for the process

Text Solution

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Here, `n = 2` moles , `T = 27^(@) C=300 K, P _(1)= 1 atm,P _(2) =10 atm`
`w= 2.303n RT log. (P_(2))/(P_(1)) = 2.303 xx 2 mol xx 8.314 JK^(-1) mol^(-1) xx 300 K xx log. (10)/(1) = 11488 J `
For isothermal compressionof ideal gas, `Delta U = 0`
Further, `Delta U = q+w :. q = -w = -11488J`
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Knowledge Check

  • At 27^(@)C , one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm to 10 atm. The values of DeltaE and q are (R=2)

    A
    `0, -965.84 cal`
    B
    `-965.84 cal, + 965.84 cal`
    C
    `+ 865.58 cal, -865.58 cal`
    D
    `-865.58 cal, -865.58 cal`

  • At 27^(@)C one mole of an ideal gas is compressed isothermally and reversibly from a pressure of 2 atm to 10 atm. The value of DeltaE and q are (R=2 cal)

    A
    `0,-965.84 cal`
    B
    `-965.84 cal,-865.58cal`
    C
    `+865.58cal,-865.58cal`
    D
    `+965.84cal,+865.58cal`

  • 10 moles of an ideal gas are compressed isothermally and reversibly at 200°C from a pressure of 1 atm to a pressure of S atm. Then

    A
    `DeltaU=0,DeltaH=0`
    B
    `DeltaUne0,DeltaH=0`
    C
    `DeltaU=0,DeltaHne0`
    D
    `DeltaUne0,DeltaHne0`