The heat evolved in the combustion of glucose is shown in the equation `:`
`C_(6)H_(12)O_(6)(s) + 6O_(2)(g) rarr 6CO_(2)(g) + 6H_(2)O (g) , Delta_(c ) H = -2840 kJ mol^(-1)`
What is the energy requirement for production of 0.36g of glucose by the reverse reaction ?

Explanation

To solve the problem, we need to calculate the energy requirement for the production of 0.36 g of glucose (C₆H₁₂O₆) by the reverse reaction of its combustion. The combustion reaction is given as:

\[ C_6H_{12}O_6 (s) + 6O_2 (g) \rightarrow 6CO_2 (g) + 6H_2O (g) \]
\[ \Delta_c H = -2840 \, \text{kJ/mol} \]

### Step-by-Step Solution:

**Step 1: Determine the molar mass of glucose (C₆H₁₂O₆).**
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