Standard vaporisation enthalpy of benzene at its boiling point is 230.8 kJ `mol^(-1)` . For how long would a 100 W electric heater have to operate to vaporize a 100 g sample of benezene at its boiling temperature ? ( power `=` energy `//` time , 1 W `= 1 J s^(-1))`

Explanation

To solve the problem, we need to find out how long a 100 W electric heater would need to operate to vaporize a 100 g sample of benzene, given that the standard vaporization enthalpy of benzene at its boiling point is 230.8 kJ/mol.

### Step-by-Step Solution:

1. **Determine the molar mass of benzene (C6H6)**:
- The molar mass of carbon (C) = 12 g/mol
- The molar mass of hydrogen (H) = 1 g/mol
- Molar mass of benzene = (6 × 12) + (6 × 1) = 72 + 6 = 78 g/mol
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