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Calculate the enthalpy change for the re...

Calculate the enthalpy change for the reaction `H_(2)(g) + Br_(2)rarr 2HBr (g)` Give that the bond enthalpies ofH-H,Br-Br and H-Br are435, 192 and 364kJ `mol^(-1)` respectively.

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To calculate the enthalpy change for the reaction \[ H_2(g) + Br_2(g) \rightarrow 2HBr(g) \] we will use the bond enthalpy values provided. The bond enthalpy is the energy required to break a bond in one mole of a substance in the gas phase. ### Step 1: Identify the bonds broken and formed ...
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Use the bond enthalpies listed below to estimate the enthalpy change for the reaction H_(2)(g)+Br_(2)(g)rarr2HBr(g) Given: BE of H_(2), Br_(2) , and HBr is 435, 192 , and 368 kJ mol^(-1) , respectively.

The net enthalpy change of a reaction is the amount of energy required to break all the bonds in reactant molecules minus amount of energy required to form all the bonds in the product molecules.What will be the enthalpy change for the following reaction. H_(2)(g) + Br_(2)(g) to 2HBr(g) Given that bond energy of H_(2), Br_(2) and HBr is 435 kJ mol^(-1) , 192 kJ mol^(-1) and 368 kJ mol^(-1) respectively.

The enthalpy change for the reaction, C_(2)H_(6)(g)rarr2C(g)+6H(g) is X kJ. The bond energy of C-H bond is :

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