Propane has the structure `H_(3)C - CH_(2) - CH_(3)` . Calculate the change in enthalpy for the reaction `:`
`C_(3) H_(8) (g) + 5O_(2)(g) rarr 3 CO_(2)(g) + 4H_(2)O(g)`
Given that average bond enthalpies are `:`
`{:(C-C,C-H,C=0,O=O,O-H),(347,414,714,498,464kJ mol^(-1)):}`

Explanation

To calculate the change in enthalpy (ΔH) for the combustion reaction of propane, we will use the average bond enthalpies provided. The reaction is:

\[ \text{C}_3\text{H}_8(g) + 5\text{O}_2(g) \rightarrow 3\text{CO}_2(g) + 4\text{H}_2\text{O}(g) \]

### Step 1: Identify the bonds in the reactants and products

**Reactants:**
- Propane (C₃H₈) has:
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