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Determine the value of DeltaH and DeltaU...

Determine the value of `DeltaH` and `DeltaU` for the reversible isothermal evaporation of 90.0g of water at `100^(@)C`.Assume that water vapour behaves as an ideal gas and heat of evaporation of water is `540 calg^(-)R = 2.0 cal mol^(-1)K^(-1)`.

Text Solution

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The correct Answer is:
`Delta H = 48600 cal, Delta U = 44870cal`
`DeltaH = 540 xx 90 cal = 48600 cal, DeltaU = DeltaH - Deltan_(g)RT`,
`90 g H_(2) O = 5 ` moles , `Delta n_(g) = 5 ` for moles of `H_(2)O(l) rarr 5` moles of `H_(2)O(g)`
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