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10 mL of H(2)O(2) solution is treated wi...

10 mL of `H_(2)O_(2)` solution is treated with KI and titration of liberated `I_(2)` required 10 mL of 1 N hypo . Thus `H_(2)O_(2)` is

A

1N

B

5.6 volume

C

`17 gL^(-1)`

D

all are correct

Text Solution

Verified by Experts

The correct Answer is:
D
Let the normality of `H_(2)O_(2)=N_(1)`
`therefore N_(1)xx10(H_(2)O_(2))=1xx10(Na_(2)S_(2)O_(3))`
`therefore ` Normality of `H_(2)O_(2)` solution =1N
`1NH_(2)O_(2)=5.6 vol. H_(2)O_(2)=17 gL^(-1)`
Therefore , all statement are correct.
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