The strength of `H_(2)O_(2)` (in g/litre) in 11.2 volume solution of `H_(2)O_(2)` is

Options

A. 17
B. 51
C. 34
D. 85

Explanation

To find the strength of hydrogen peroxide (H₂O₂) in grams per liter for a solution with a volume strength of 11.2, we can follow these steps:

### Step 1: Understand the relationship between volume strength and concentration
The volume strength of a solution is defined as the volume of oxygen gas (in liters) that can be produced from 1 liter of the solution at standard temperature and pressure (STP). The formula relating volume strength (V) to the strength (S) in grams per liter and the equivalent weight (E) is given by:

\[ V = \frac{5.6 \times S}{E} \]

### Step 2: Determine the equivalent weight of H₂O₂
The equivalent weight of hydrogen peroxide can be calculated using its molecular weight and the n-factor. The molecular weight of H₂O₂ is 34 g/mol. Since H₂O₂ can donate 2 moles of hydrogen ions (H⁺), its n-factor is 2.

Thus, the equivalent weight (E) of H₂O₂ is calculated as:

\[ E = \frac{\text{Molecular weight}}{\text{n-factor}} = \frac{34}{2} = 17 \, \text{g/equiv} \]

### Step 3: Substitute the known values into the formula
Now we can substitute the known values into the volume strength formula. We have:

- Volume strength (V) = 11.2
- Equivalent weight (E) = 17

Substituting these values into the formula:

\[ 11.2 = \frac{5.6 \times S}{17} \]

### Step 4: Solve for the strength (S)
To find the strength (S), we can rearrange the equation:

\[ S = \frac{11.2 \times 17}{5.6} \]

Calculating the right side:

\[ S = \frac{190.4}{5.6} = 34 \, \text{g/L} \]

### Conclusion
The strength of the H₂O₂ solution is **34 grams per liter**.