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In transforming 0.01 mole of PbS to PbSO...

In transforming `0.01` mole of `PbS` to `PbSO_(4)`, the volume of '10 volume `H_(2)O_(2)` required will be `:`

A

11.2 mL

B

22.4 mL

C

33.6 mL

D

44.8 mL

Text Solution

Verified by Experts

The correct Answer is:
D
`underset(0.01 "mole")(PbS) + underset(0.04 "mole")(4H_(2)O_(2)) to PbSO_(4) + 4H_(2)O`
`underset(0.04 "mole")(4H_(2)O_(2)) to 4H_(2)O + underset(0.02xx22400 mL "at N.T.P.")(2O_(2))`
Vol of `O_(2)` at N.T.P. `=0.02xx22400`
`=448` mL
`therefore` Volume of 10 volume `H_(2)O_(2)` solution
`=448//10=44.8` mL.
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