Which of the following compounds are readily soluble in water ?

Options

A. `BeSO_(4)`
B. `MgSO_(4)`
C. `BaSO_(4)`
D. `SrSO_(4)`

Explanation

To determine which of the following compounds are readily soluble in water, we need to consider the solubility trends of the compounds formed by alkali and alkaline earth metals. Here’s a step-by-step solution:

### Step 1: Identify the Compounds
First, we need to identify the compounds we are considering for solubility. Let's say the compounds are:
1. Beryllium sulfate (BeSO4)
2. Magnesium sulfate (MgSO4)
3. Barium sulfate (BaSO4)
4. Strontium sulfate (SrSO4)

### Step 2: Understand Solubility Trends
The solubility of compounds formed by alkaline earth metals in water generally decreases as we move down the group in the periodic table. This is due to the increase in ionic size and the corresponding decrease in hydration energy.

### Step 3: Analyze Hydration Energy
Hydration energy is the energy released when ions are surrounded by water molecules. For a compound to be soluble, the hydration energy must be greater than the lattice energy (the energy required to separate the ions in the solid). As we move down the group:
- Beryllium (Be) has the smallest ionic size and the highest hydration energy.
- Magnesium (Mg) is next, with slightly lower hydration energy.
- Strontium (Sr) and Barium (Ba) have larger ionic sizes and lower hydration energies.

### Step 4: Compare the Compounds
Now, let's compare the solubility of the compounds:
- **BeSO4**: This compound is soluble in water due to high hydration energy.
- **MgSO4**: This compound is also soluble in water.
- **SrSO4**: This compound has low solubility in water.
- **BaSO4**: This compound is poorly soluble in water.

### Step 5: Conclusion
From the analysis, we conclude that the compounds that are readily soluble in water are:
- Magnesium sulfate (MgSO4)
- Beryllium sulfate (BeSO4)

### Final Answer
The compounds that are readily soluble in water are **BeSO4 and MgSO4**.

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